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George spent 80% of his savings to buy a camera. The camera cost $580. How much did he have in savings before he bought the camera?​

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Answer:

George had $725 in savings

Explanation:

Let's assume that George had x dollars in savings before he bought the camera.

According to the problem, George spent 80% of his savings to buy the camera, which means he had 20% of his savings left after the purchase. We can write this as:

0.20x = amount of savings left after buying the camera

We also know that the camera cost $580. We can set up an equation to relate the cost of the camera to the amount of savings that George had before buying the camera:

0.80x = $580

Solving for x, we get:

x = $580 / 0.80

x = $725

Therefore, George had $725 in savings before he bought the camera.

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User Prasadmadanayake
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