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Three corners of a rectangular city block are located at (2,2), (2,-4) and (-5,-4) on a coordinate plane. What are the coordinates of the fourth corner

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User Drewtato
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1 Answer

2 votes

Answer:

(-11,8)

Explanation:

To find the coordinates of the fourth corner of the rectangular city block, we need to use the fact that opposite sides of a rectangle are parallel and equal in length.

Let's start by finding the length of one of the sides of the rectangle. We can use the distance formula for that:

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

For example, if we want to find the length of the side between (2,2) and (2,-4), we have:

d = sqrt((2 - 2)^2 + (-4 - 2)^2) = sqrt(6^2) = 6

We can also see from the given coordinates that the sides of the rectangle are parallel to the x or y axis, which means that their lengths are simply the difference between the corresponding x or y coordinates.

So now we know that the length of the sides of the rectangle are both 6 units. The missing corner must be positioned 6 units away from the given point (-5,-4) along the x-axis, since the fourth side of the rectangle is parallel to the x-axis. Therefore, its x-coordinate is -5 - 6 = -11.

Similarly, the fourth corner must be positioned 6 units away from the given point (2,2) along the y-axis, since the fourth side of the rectangle is parallel to the y-axis. Therefore, its y-coordinate is 2 + 6 = 8.

Therefore, the coordinates of the fourth corner are (-11, 8).

answered
User Ricmarchao
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