Question

8y^2+6xy

evaluate the given polynomial at:

x=3, y=1

. Replace the variable(s) in the polynomial with the specific value(s) given and determine the value of the polynomial by performing the indicated operations.

Answer 1

Putting the values of x and y in the given polynomial

`= 8({1})^(2) + 6(3)(1)`

`= 8(1) + 18`

`= 8 + 18`

`= 26`

Hence the value of polynomial is 26