Question

When Nevaeh goes bowling, her scores are normally distributed with a mean of 165 and a standard deviation of 13. Out of the 90 games that she bowled last year, how many of them would she be expected to score less than 193, to the nearest

whole number?

Answer 1

To find the number of games Nevaeh would be expected to score less than 193, calculate the z-score for that value, which is about 2.15. Using a z-table or calculator, the probability associated with a z-score of 2.15 is approximately 0.983. Therefore, Nevaeh would be expected to score less than 193 in approximately 98.3% of the 90 games she bowled last year.

Step-by-step explanation:

To find the number of games Nevaeh would be expected to score less than 193, we need to calculate the z-score for that value.

The formula to calculate the z-score is:

z = (x - mean) / standard deviation

Plugging in the values:

z = (193 - 165) / 13

z ≈ 2.15

Using a z-table or calculator, we can find the probability associated with a z-score of 2.15. The probability is approximately 0.983.

So, Nevaeh would be expected to score less than 193 in approximately 98.3% of the 90 games she bowled last year.