asked 177k views
4 votes
what is the ph of a solution made by mixing 5.00 ml of 0.105 m koh with 15.0 ml of 9.5 x 10-2 m ca(oh)2?

1 Answer

0 votes

Answer:

0.773

Step-by-step explanation:

To find the pH of the solution, we need to determine the concentration of hydroxide ions (OH-) in the solution, as pH is defined as the negative logarithm of the hydrogen ion (H+) concentration, and in a basic solution, the concentration of OH- is greater than that of H+.

First, let's calculate the moles of OH- that will be present in the solution. We can do this by using the following equation:

moles of OH- = concentration x volume

For the KOH solution:

moles of OH- = 0.105 M x 0.00500 L = 0.000525 moles

For the Ca(OH)2 solution:

moles of OH- = 9.5 x 10^-2 M x 0.0150 L x 2 = 0.00285 moles (Note: we multiply by 2 because there are two moles of OH- per mole of Ca(OH)2)

The total moles of OH- in the solution is the sum of the moles from the two solutions:

total moles of OH- = 0.000525 moles + 0.00285 moles = 0.003375 moles

Next, we can calculate the total volume of the solution:

total volume = 5.00 mL + 15.0 mL = 20.0 mL = 0.0200 L

Now we can calculate the concentration of OH-:

OH- concentration = moles of OH- / total volume

OH- concentration = 0.003375 moles / 0.0200 L

OH- concentration = 0.16875 M

Finally, we can find the pH of the solution:

pH = -log[OH-]

pH = -log(0.16875)

pH = 0.773

answered
User David Monniaux
by
8.3k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.