Question

Hello,

I'm new here and i just wanted to know if someone could help me with my math question.


Agyapong is three times as old as musah. three years ago, he was four times as old as musah. how old is each boy now?
​

Answer 1

Let's use algebra to solve this problem.

Let A be the current age of Agyapong, and let M be the current age of Musah.

From the problem, we know that:

A = 3M (Agyapong is three times as old as Musah)

A - 3 = 4(M - 3) (Three years ago, Agyapong was four times as old as Musah)

We can simplify the second equation by distributing the 4:

A - 3 = 4M - 12

Now we can substitute the first equation into the second equation:

3M - 3 = 4M - 12

Simplifying this equation, we get:

M = 9

So Musah is currently 9 years old.

Using the first equation, we can find Agyapong's age:

A = 3M = 3(9) = 27

So Agyapong is currently 27 years old.