Answer:
First, we need to calculate the molar mass of LiF:
LiF: Li = 6.941 g/mol, F = 18.998 g/mol
1 Li + 1 F = 6.941 g/mol + 18.998 g/mol = 25.939 g/mol
So, 1 mole of LiF weighs 25.939 g.
Now, we can calculate how many moles of LiF are in 30.0 g:
moles = mass ÷ molar mass
moles = 30.0 g ÷ 25.939 g/mol
moles = 1.157 mol
Finally, we can use the formula for molarity to find the volume of the solution:
Molarity = moles ÷ volume (in liters)
We want to solve for volume in milliliters, so we can rearrange the formula:
Volume (in liters) = moles ÷ molarity
Volume (in mL) = (moles ÷ molarity) × 1000
Plugging in the values, we get:
Volume (in mL) = (1.157 mol ÷ 0.650 mol/L) × 1000 = 1778.5 mL
Rounding to three significant figures, the answer is:
The solution contains 1780 mL of 0.650 M LiF.