Final answer:
The anode half-reaction is Zn(s) -> Zn²+(aq) + 2e^-. The cathode half-reaction is Ag²O(s) + H2O(l) + 2e^- -> 2Ag(s) + 2OH^-(aq). The overall cell reaction is Zn(s) + 2Ag²O(s) + 2H2O(l) -> Zn²+(aq) + 2Ag(s) + 4OH^-(aq).
Step-by-step explanation:
The balanced half-reaction that occurs at the anode during discharge is:
Zn(s) -> Zn^2+(aq) + 2e^-
The balanced half-reaction that occurs at the cathode during discharge is:
Ag^2O(s) + H2O(l) + 2e^- -> 2Ag(s) + 2OH^-(aq)
The balanced overall cell reaction that occurs during discharge is:
Zn(s) + 2Ag^2O(s) + 2H2O(l) -> Zn^2+(aq) + 2Ag(s) + 4OH^-(aq)