Question

6. A sealed flask filled with an ideal gas is moved from an ice bath into a hot water bath. The initial temperature is 273K and

the final temperature is 350 K. The initial pressure is 100kPa. The volume does not change. What is the final pressure of the flask? Name the gas law.

Answer 1

Step-by-step explanation:

Since the volume of the gas does not change, we can use the Gay-Lussac's law (also known as Pressure-Temperature law), which states that the pressure of an ideal gas is directly proportional to its absolute temperature when the volume is kept constant. Mathematically, this can be expressed as:

P1/T1 = P2/T2

where P1 and T1 are the initial pressure and temperature, respectively, and P2 and T2 are the final pressure and temperature, respectively.

Substituting the given values in the above equation, we get:

P2 = (P1/T1) × T2

= (100 kPa/273 K) × 350 K

= 128.83 kPa (approx.)

Therefore, the final pressure of the flask is approximately 128.83 kPa.