Question

3. A solution of hydrochloric acid is made by dissolving hydrogen chloride gas in 100.0ml water. This solution neutralizes a 15ml sample of 0.10 mol/L sodium carbonate solution. a. What mass of hydrogen chloride gas was dissolved in 100.0ml of water? b. What volume of hydrogen chloride was this?​

Answer 1

Okay, here are the steps to solve this problem:

a) To neutralize 15ml of 0.10 mol/L sodium carbonate solution, the hydrochloric acid solution must contain 0.015 moles of HCl.

Since the HCl solution is made by dissolving HCl gas in 100ml water, we can calculate the moles of HCl gas dissolved in 100ml:

0.015 moles HCl / 15ml sodium carbonate solution = X moles HCl gas / 100ml HCl solution

X = 0.015 * (100/15) = 0.01 moles HCl gas

b) Molar volume of HCl gas at STP is 24.45 L/mol.

So the volume of 0.01 moles HCl gas is: 0.01 moles * 24.45 L/mol = 0.2445 L

Since the solution is made with this gas in 100ml water, the volume of HCl gas dissolved in 100ml water is 0.2445 L.

So the final answers are:

a) 0.01 moles of HCl gas

b) 0.2445 L of HCl gas

Please let me know if you have any other questions!