Question

What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to the line whose equation is

4x+y-2=0?
04x-y=13
4x+y=13
4x+y=-13

Answer 1

4x + y = 13

Explanation:

The original equation is: 4x + y - 2 = 0 --> y = -4x + 2

Equation 1: 4x - y = 13 --> y = 4x - 13. Since it does not have the same slope as the original equation, Equation 1 is not the answer.

Equation 2 turns into y = -4x + 13. -3 = -4(4) + 13 = -16 + 13 = -3. Since the equation passes through this point and has the same slope as the original equation, it fits the criteria for the problem.