Answer:
to express the quadratic equetion in to factor form
you must use completing squere method

y + 5 = x2 - 10x
y + 5 = x2 - 10xy + 5 + 25 = x2 - 10x + 25
y + 5 = x2 - 10xy + 5 + 25 = x2 - 10x + 25y + 30 = (x - 5)2
y + 5 = x2 - 10xy + 5 + 25 = x2 - 10x + 25y + 30 = (x - 5)2 y = ( x - 5)2 - 30 so we get the factor form of the quadratic equetion.
In other way :
if you need to get vertex (5, -30)
or simply by (x, f(x)) which is (-b/2a,f(-b/2a)) form
a=1
a=1b=-10
a=1b=-10c=-5
so when u substitute and you will get (5, f(5))
then for the y-coordinate you substitute 5 in place of x and you will get -30 so vertex = (5, -30)