Question

A gas collected when pressure is 800.0 mmHg has a volume of 380.0 mL. What volume, in mL, will the gas occupy at standard pressure? Assume

temperature and number of moles are held constant.

Answer 1

Step-by-step explanation:

To solve this problem, we can use Boyle's Law, which states that the product of the pressure and volume of a gas is constant as long as the temperature and number of moles of the gas are held constant.

If we assume that the initial pressure is 800.0 mmHg and the initial volume is 380.0 mL, we can write:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, and P2 and V2 are the new pressure and volume.

Since we want to find the new volume at standard pressure (which is 760.0 mmHg), we can set P2 = 760.0 mmHg and solve for V2:

P1V1 = P2V2

800.0 mmHg × 380.0 mL = 760.0 mmHg × V2

V2 = (800.0 mmHg × 380.0 mL) / 760.0 mmHg

V2 = 400.0 mL

Therefore, the gas will occupy a volume of 400.0 mL at standard pressure.