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In a right triangle, cos (62-x° = sin (48 - 4.1x)°. Determine the value of x to the nearest tenth. A 90 B 4 C -4.4 D 4.4

In a right triangle, cos (62-x° = sin (48 - 4.1x)°. Determine the value of x to the nearest tenth. A 90 B 4 C -4.4 D 4.4
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In a right triangle, cos (62-x° = sin (48 - 4.1x)°. Determine the value of x to the nearest tenth.

A 90
B 4
C -4.4
D 4.4

asked
User Shalah
by
8.6k points

1 Answer

3 votes
The answer is B

If you want proof on how I got it comment!
answered
User Mussawir Ahmad Paul
by
7.9k points
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