Answer:
If a pipe is open at both ends, the frequency of the note corresponding to the fundamental mode is given by:
f = v/2L
where f is the frequency of the note, v is the speed of sound in air, and L is the length of the pipe. The fundamental mode is the first harmonic, and it has one antinode in the center of the pipe and two nodes at the ends. Since the pipe is open at both ends, the distance between the nodes is equal to the length of the pipe, which is L.
Therefore, the frequency of the note corresponding to the fundamental mode is:
f = v/2L
Step-by-step explanation: