Question

One number is 10 more than fifteen times another. Their sum is 42. Find the numbers.

Answer 1

40, 2

Explanation:

x = number 1

y = number 2

x = 15y + 10

x + y = 42

we use the first in the second equation and get

15y + 10 + y = 42

16y = 32

y = 32/16 = 2

x + y = 42

x + 2 = 42

x = 40

Answer 2

Let's call the first number "x" and the second number "y".

From the problem, we know that:

- x = 15y + 10 (since "One number is 10 more than fifteen times another")
- x + y = 42 (since "Their sum is 42")

We can use substitution to solve for one of the variables. Substituting the first equation into the second equation, we get:

(15y + 10) + y = 42

Simplifying the left side, we get:

16y + 10 = 42

Subtracting 10 from both sides, we get:

16y = 32

Dividing both sides by 16, we get:

y = 2

Now that we know y, we can use the first equation to solve for x:

x = 15y + 10
x = 15(2) + 10
x = 40

Therefore, the two numbers are 2 and 40.