Question

In the figure the distances are: AC= 10m, BD=15m and AD=22m. Find the distance BC

Answer 1

AD-BD=22-15=7

AB is equal to 7.

AD-AC=22-10

AB is equal to 12.

AB+CD=7+12=19.

AD-(AB+CD)=22-19=3

Answer 2

3

Explanation:

As you can see from the image attached, the length of BC = 3 because:

AC= 10m, BD=15m and AD=22m

When we add up AC + BD = 25 but the length of AD is 22, the 3 extra from the sum of AC + BD is the length of BC.