Question

Calculate the molarity when 345.0g of Na2SO4, is dissolved to make a 1.650L. solution. (include units and round to 4 sig figs)

Answer 1

Therefore, the molarity of the solution is 1.471 M (molar)

Step-by-step explanation:

To calculate the molarity of a solution, we need to know the moles of solute (Na2SO4) and the volume of the solution (in liters).

First, let's calculate the moles of Na2SO4:

molar mass of Na2SO4 = 2(22.99 g/mol) + 1(32.06 g/mol) + 4(16.00 g/mol) = 142.04 g/mol

moles of Na2SO4 = (mass of Na2SO4) / (molar mass of Na2SO4)

moles of Na2SO4 = 345.0 g / 142.04 g/mol

moles of Na2SO4 = 2.430 mol

Next, let's calculate the molarity of the solution:

Molarity = (moles of solute) / (volume of solution in liters)

Molarity = 2.430 mol / 1.650 L

Molarity = 1.471 M

Therefore, the molarity of the solution is 1.471 M (molar)