Answer:
Step-by-step explanation:To determine the line of reflection, we need to find the equation of the line that is equidistant from each vertex of the original triangle and the corresponding vertex of the reflected triangle.
First, let's find the coordinates of the image of each vertex under the reflection. Since F' is given as (2, 2), we can reflect F across the unknown line of reflection to find the image of D and E. The line of reflection must be equidistant from each of these pairs of corresponding points.
To reflect F across a vertical line, the x-coordinate of F' must be the same as that of F but with the opposite sign. The x-coordinate of F is -2, so the x-coordinate of its image F' must be 2. Similarly, the y-coordinate of F' is 2, which means that the line of reflection must pass through the point (2, 2).
To reflect D across the same line, we can draw a perpendicular bisector between D and its image D', which must intersect the line of reflection at a right angle. The midpoint of DD' lies on the line of reflection, and it is equidistant from D and D'. Using the midpoint formula, we find the midpoint of DD' to be ((-3+2)/2, (5+2)/2) = (-0.5, 3.5). Since this point lies on the line of reflection, we can use the point-slope form of a line to find the equation of the line passing through (2, 2) and (-0.5, 3.5):
(y - 2) = m(x - 2) (where m is the slope of the line of reflection)
Simplifying:
y - 2 = m(x - 2)
y = mx - 2m + 2
To find the value of m, we can use the fact that the midpoint of DE lies on the line of reflection as well. The midpoint of DE is ((-3-10)/2, (5+4)/2) = (-6.5, 4.5). Substituting these values into the equation of the line, we get:
4.5 = m(-6.5) - 2m + 2
2.5 = -8.5m
m = -0.294
Therefore, the equation of the line of reflection is:
y = -0.294x + 2.588
This line is not the x-axis, y-axis or the line y=x. Therefore, the line of reflection is neither the x-axis nor the y-axis, and it is not the line y = x.