Answer: Wrote the answers below
Step-by-step explanation:
The balanced equation for Number 1 is:
Fe2O3(s) + 3H2(g) --> Fe(s) + 3H2O(l)
Step 1:
moles ratio of iron (III) oxide and hydrogen is 1:3
step 2:
work out mr (molar mass) of fe2o3: 111.68+ 48 = 159.68
moles of iron (III) oxide: 33.5g divided by 159.68 = 0.21 mol
Step 3:
1:3 ratio so 0.21 times 3 = 0.63 mol of hydrogen
Step 4:
mass of hydrogen = mol times mr
0.63 times 2 = 1.26g
mass of hydrogen = 1.26g or 1.27g depending on whether you used 1.00 or 1.01 for the mr of hydrogen