Question

A)
11. How many milliliters of 1.50M KOH solution are needed to provide 0.125mol KOH?

Answer 1

83.3 mL is required to provide 0.125mol KOH

Step-by-step explanation:

We know that,

V=
`(n)/(c)` where n=number of moles, c= concentration and V=volume

According to the question,

c=1.50M and n=0.125 mol

Substituting the values,

V=
`(0.125mol)/(1.50M)`

=0.0833L

The volume should be in mL,

0.0833L×
`(1000mL)/(1L)`

= 83.3mL