Answer:
Let xxx be the number of days Addison can afford to rent.
The cost of renting the car for xxx days is 20*x.
The cost of driving 100 miles is 0.10*100 = 10.
The total cost of renting the car and driving is 20*x + 10.
Addison wants to spend at most $80, so we have the inequality 20*x + 10 <= 80.
Solving for xxx, we get x <= 3.
Therefore, Addison can afford to rent the car for at most 3 days.