asked 6.8k views
2 votes
in a race in which 9 contestants are entered in how many ways can first second and third place be awarded

asked
User Tombul
by
8.7k points

1 Answer

4 votes

Answer: 504 different ways.

Explanation:

This situation uses a permutation. We will use the given formula and simplify to solve. n is equal to the number of contestants and r is 3 since we are selecting and first-, second-, and third-place winner.

Given:


\displaystyle P = (n!)/((n-r)!)

Substitute values:


\displaystyle P = (9!)/((9-3)!)

Subtract:


\displaystyle P = (9!)/(6!)

Multiply:


\displaystyle P = (9*8*7*6*5*4*3*2*1)/(6*5*4*3*2*1)

Simplify using the knowledge that something divided by itself is 1:

P = 9 * 8 * 7

Multiply:

P = 504

We can also think of it as 9 different people could win 1st, 8 different people could win 2nd, and 7 different people could win 3rd. 9 * 8 * 7 = 504. However, the steps above show why this works with the formula as well.

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