asked 88.2k views
2 votes
Write a cosine function that has an amplitude of 2, a midline of y=3 and a period of 2/7​

asked
User Fmg
by
8.1k points

1 Answer

5 votes

Answer:

f(x) = 2 cos[7π x] + 3

Explanation:

The general form of a cosine function with amplitude A, midline y=m, and period P is:

f(x) = A cos[(2π/P) x] + m

Using the given values, we can substitute A=2, m=3, and P=2/7​ to get:

f(x) = 2 cos[(2π/(2/7)) x] + 3

Simplifying the expression inside the cosine function:

f(x) = 2 cos[7π x] + 3

This is a cosine function with an amplitude of 2, a midline of y=3, and a period of 2/7.

answered
User BTL
by
7.6k points
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