Question

A spinner is divided into 10 equally sized sectors. The sectors are numbered 1 to 10. A randomly selected point is chosen.

What is the probability that the randomly selected point lies in a sector that is a multiple of 3?

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Answer 1

Answer:3/10 or 30%

Explanation:

the sectors are 1 through 10 meaning 1 2 3 4 5 6 7 8 9 10 out of all those numbers the only ones divisible by 3 is 3 6 9 meaning that 3 numbers out of 10 are divisible by 3. therefore being 3/10.

Answer 2

Answer: 0.3 or 30%

Explanation:

Is is given that a spinner has sections labeled 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10. Of these ten values, 3, 6, and 9 are multiples of 3. A multiple is a number that can be divided by that number without a reminder (ex: 9 ÷ 3 = 3).

We will divide the total number of "wanted outcomes" by the total number of "possible outcomes" when the spinner is spun.

`\displaystyle (wanted)/(possible) =(3,6,9)/(1, 2, 3, 4, 5, 6, 7, 8, 9, 10) =(3)/(10) =0.3\;\;or\;\;30\%`