Calculate the volume that 4.5 kg of ethylene gas (C₂H₂) will occupy at STP

Question

asked Jan 16, 2024 133k views

1 Answer

Lancepants · Answer 1 · 2024-01-21T11:51:03+0000

Answer:

3, 876.9 ~ 3, 877

Step-by-step explanation:

4.5 kg = 4500 g....... convert to gram

n =m/M , n= no of mol

m= mass of sub.

M= molar mass

so n= 4500g / 26g/mol

n= 173.076 mol

then 1 mol = 22.4 L ............... at STP

at STP 173.076 mol = X

then when u solve X by

X = (173.076 mol × 22.4 L)/ 1 mol

X = 3, 876.9 L at STP which is aproximate to

3, 877L at STP