Question

When you push a 1.88-kg book resting on a tabletop, you have to exert a force of 2.10 N to start the book sliding. Once it is sliding, however, you can use a force of only 1.01 N to keep the book moving with constant speed.

Answer 1

The coefficient of static friction between the book and the tabletop is:

fs = 2.10 N / 1.88 kg = 1.12

The coefficient of kinetic friction between the book and the tabletop is:

f k = 1.01 N / 1.88 kg = 0.537

The coefficient of static friction is greater than the coefficient of kinetic friction. This is because it is harder to start an object moving than to keep it moving once it is already in motion.

Step-by-step explanation: