Question

HELPPP ASAP!!

On the coordinate plane, AMNO has vertices M(4, 4), N(5, -7), and 0(-6, -6). What is the perimeter of AMNO? If necessary, round your answer to the nearest tenth. ​

Answer 1

To find the perimeter of a polygon, we need to add up the lengths of all its sides.

The length of a side can be found using the distance formula, which is:

d = √[(x2 - x1)² + (y2 - y1)²]

Using this formula, we can find the lengths of the sides of triangle AMN:

d(MN) = √[(5 - 4)² + (-7 - 4)²] = √(1² + (-11)²) = √(1 + 121) = √122

d(NA) = √[(-6 - 5)² + (-6 - (-7))²] = √((-11)² + 1²) = √(121 + 1) = √122

d(AM) = √[(4 - (-6))² + (4 - (-6))²] = √(10² + 10²) = √200

So the perimeter of AMNO is:

P = d(MN) + d(NA) + d(AM) = √122 + √122 + √200 ≈ 24.3 (rounded to the nearest tenth)

Therefore, the perimeter of AMNO is approximately 24.3 units.