We can use Newton's law of cooling to solve this problem:
T(t) = T_a + (T_0 - T_a) * e^(-kt)
where T(t) is the temperature of the object at time t, T_a is the ambient temperature, T_0 is the initial temperature of the object, and k is a constant. We can solve for k by using the information that the object cools from 200 degrees to 131 degrees in 5 minutes:
131 = 20 + (200 - 20) * e^(-5k)
Simplifying this equation, we get:
e^(-5k) = 0.625
Taking the natural logarithm of both sides, we get:
-5k = ln(0.625)
k = -ln(0.625) / 5
k ≈ 0.1078
Now we can use this value of k to find the temperature of the object after 9 minutes:
T(9) = 20 + (200 - 20) * e^(-0.1078 * 9)
T(9) ≈ 94.9 degrees Celsius
Therefore, the temperature of the object at the end of 9 minutes will be approximately 94.9 degrees Celsius.