Answer:
F1 = 35 N F2 = 55 N
There will be no sidewise force on the resultant force
F1 sin θ1 = F2 sin (90 - θ1) since the ropes are at right angles
35 sin θ1 = 55 cos θ1 cos θ1 = sin (90 - θ1)
tan θ1 = 55 / 35 = 1.57 θ1 = 57.5 deg 90 - θ1 = 32.5 deg
F1 cos 57.5 + F2 cos 32.5 = 35 cos 57.5 + 55 cos 32.5 = 65.2 N
R (resultant) = 65.2 N
a = 65.2 N / 50 kg = 1.30 m/s^2
A) is correct