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Two square carpets are used in the reception area of a hotel. The sum of the areas of the carpets is 720 square feet. The difference of the areas of the carpets is 432 square feet. Find the dimensions of each carpet.

asked
User GFlam
by
7.2k points

1 Answer

4 votes

Answer:

Let x be the length of one side of the first carpet in feet. Then, the area of the first carpet is x^2 square feet.

Let y be the length of one side of the second carpet in feet. Then, the area of the second carpet is y^2 square feet.

From the problem, we know that the sum of the areas of the two carpets is 720 square feet:

x^2 + y^2 = 720

We also know that the difference of the areas of the two carpets is 432 square feet:

x^2 - y^2 = 432

We can solve this system of equations by using the method of substitution. Solving for x^2 in the second equation, we get:

x^2 = y^2 + 432

Substituting this expression for x^2 into the first equation, we get:

y^2 + 432 + y^2 = 720

Simplifying and solving for y, we get:

2y^2 = 288

y^2 = 144

y = 12

Substituting this value of y into the equation x^2 + y^2 = 720 and solving for x, we get:

x^2 + 144 = 720

x^2 = 576

x = 24

Therefore, the dimensions of the first carpet are 24 feet by 24 feet, and the dimensions of the second carpet are 12 feet by 12 feet.

Explanation:

answered
User Amespower
by
8.3k points
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