Question

For the function -3x^2+12

find the coordinates of the vertex of its graph

Answer 1

To find the coordinates of the vertex of the graph of the function -3x^2+12, we can use the formula x = -b/2a to find the x-coordinate of the vertex, and then substitute it back into the function to find the y-coordinate.

In this case, the function is in the form f(x) = -3x^2+12, so we can see that a = -3 and b = 0.

Using the formula x = -b/2a, we get:

x = -0/(2*(-3)) = 0

So the x-coordinate of the vertex is 0.

To find the y-coordinate of the vertex, we can substitute x = 0 into the function:

f(0) = -3(0)^2+12 = 12

So the y-coordinate of the vertex is 12.

Therefore, the coordinates of the vertex of the graph of the function -3x^2+12 are (0, 12).

Explanation:

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