Question

Adult tickets to a basketball game cost $5. Student tickets cost $1. A total of $2,366 was collected on the sale of 1,098 tickets. How many of each type of ticket were sold?

Answer 1

x+y= 1098

5x+1y= 2366

y= 1098 - x

5x+ 1(1098-x) = 2366

5x + 1098 - x = 2366

4x= 1268

x= 317

x+y= 1098

317 + y= 1098

y= 781

So the answer is: 317 adult tickets and 781 student tickets were sold.

Answer 2

Explanation:

Using algebra to solve this problem

Let x be the number of adult tickets sold and y be the number of student tickets sold. We can set up a system of two equations to represent the information given in the problem:

x + y = 1098 (equation 1) (the total number of tickets sold is 1,098)
5x + 1y = 2366 (equation 2) (the total amount collected is $2,366)

To solve for x and y, we can use substitution or elimination method. Let's use the substitution method.

From equation 1, we can solve for y as follows:

y = 1098 - x

Substituting this expression for y into equation 2, we get:

5x + 1(1098 - x) = 2366

Simplifying and solving for x, we get:

5x + 1098 - x = 2366
4x = 1268
x = 317

So, 317 adult tickets were sold. To find the number of student tickets sold, we can substitute this value for x into equation 1 and solve for y:

317 + y = 1098
y = 1098 - 317
y = 781

Therefore, 781 student tickets were sold.