Question

Juanita has 3 rectangular cards that are 5 inches by 8 inches. How can she arrange the​ cards, without​ overlapping, to make one larger polygon with the smallest possible​ perimeter? How will the area of the polygon compare to the combined area of the ​cards?

Answer 1

The way that she can arrange the cards without overlapping, to make one larger polygon with the smallest possible perimeter is:8+8+8+8+8+8+9+9=66 inches as you can see in the attached photo . The area of the polygon is equal to the combined area of the three cards without overlapping or extending

Answer 2

The way that she can arrange the cards, without overlapping, to make one larger polygon with the smallest possible perimeter is that:
Put 3 cards together according to the length
So the smallest possible perimeter is:
8 + 8+8 + 8 + 8 + 8+9 + 9 = 66 inches as you
can see in the attached photo.
The area of the polygon is equal to the combined area of the 3 cards without overlapping or extending.