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Assume 'v' being an array of long integers (64 bits), with base address stored in register x1, 'i' being a long integer residing at address 1024, translate the following codes in Assembly RISC-V:

1) v[i] = v[i] + v[i+1]
2) for(i=1; i < 10; i++){
v[i] = v[i] * v[i+1];
}

asked
User Ykay
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1 Answer

3 votes

Answer:

Here's the translation of the code into RISC-V assembly:

# Load the value of v[i]

ld x10, 1024(x0) # Load i into register x10

slli x11, x10, 3 # Multiply i by 8 to get the byte offset

add x12, x1, x11 # Add the offset to the base address to get the address of v[i]

ld x13, 0(x12) # Load the value of v[i] into register x13

# Load the value of v[i+1]

addi x10, x10, 1 # Increment i by 1 to get i+1

slli x11, x10, 3 # Multiply i+1 by 8 to get the byte offset

add x12, x1, x11 # Add the offset to the base address to get the address of v[i+1]

ld x14, 0(x12) # Load the value of v[i+1] into register x14

# Add the two values and store the result in v[i]

add x13, x13, x14 # Add v[i] and v[i+1]

sd x13, 0(x12) # Store the result in v[i]

# Initialize i to 1

li x10, 1

loop:

# Check if i < 10

bge x10, 10, exit

# Load the value of v[i]

slli x11, x10, 3 # Multiply i by 8 to get the byte offset

add x12, x1, x11 # Add the offset to the base address to get the address of v[i]

ld x13, 0(x12) # Load the value of v[i] into register x13

# Load the value of v[i+1]

addi x10, x10, 1 # Increment i by 1 to get i+1

slli x11, x10, 3 # Multiply i+1 by 8 to get the byte offset

add x12, x1, x11 # Add the offset to the base address to get the address of v[i+1]

ld x14, 0(x12) # Load the value of v[i+1] into register x14

# Multiply the two values and store the result in v[i]

mul x13, x13, x14 # Multiply v[i] and v[i+1]

sd x13, 0(x12) # Store the result in v[i]

# Increment i and jump to the beginning of the loop

addi x10, x10, 1

j loop

exit:

Step-by-step explanation:

answered
User Serenskye
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