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A block weighing 15 newtons is on a ramp inclined at 30.0º to the horizon\tal

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To solve this problem, we need to use trigonometry to find the components of the weight of the block that act parallel and perpendicular to the ramp.

The weight of the block (W) is given as 15 N. The angle of inclination of the ramp (θ) is given as 30.0º.

We can use the following equations to find the components of the weight:

W_parallel = W * sin(θ)
W_perpendicular = W * cos(θ)

Substituting the given values, we get:

W_parallel = 15 N * sin(30.0º) = 7.5 N
W_perpendicular = 15 N * cos(30.0º) = 12.99 N

Therefore, the component of the weight that acts parallel to the ramp is 7.5 N and the component that acts perpendicular to the ramp is 12.99 N.
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User Yogevnn
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