Question

4) A student applies 970 J of heat to 12.2 grams of an unknown metal. The temperature of the metal rises from 23.0°C

to 170.0°C. What is the specific heat of the metal?

Answer 1

0.541

Step-by-step explanation:

J = mass * specific heat * change in Temp

970 = 12.2 * x * 170 - 23

x = 0.541