Question

For helted Pulley, the speed of the pulley very inversly as their radio. If a pulley with a radioof 4 inches turning at 1452 resolutions per minute is helted to a pulley with a radiousof 6 inches what will be the speed of a largee pulley?

k=
Equation=
Answer=
pls help meee​

Answer 1

So, we can write the equation as:

v * k = constant

Let the constant be C. So, we have:

v1 * k = C ---(1) (for smaller pulley)
v2 * k = C ---(2) (for larger pulley)

Now, we need to find the speed of the larger pulley. We are given that a pulley with a radius of 4 inches is turning at 1452 revolutions per minute. So, we can write:

v1 = 1452 revolutions per minute (for smaller pulley)
r1 = 4 inches (for smaller pulley)
r2 = 6 inches (for larger pulley)

Since the speed of the pulley varies inversely with their radius, we can write:

v1 * r1 = v2 * r2

Substituting the values, we get:

1452 * 4 = v2 * 6

v2 = (1452 * 4) / 6

v2 = 968 revolutions per minute

Therefore, the speed of the larger pulley is 968 revolutions per minute.

We can find the value of k by using equation (2):

v2 * k = C

968 * k = C

So, k = C/968

Hence, the equation in terms of k is:

v * k = C

where k = C/968.

Answer 2

Explanation:

Answer: The speed of the larger pulley is 242 rpm.

Step-by-step explanation: We can use the fact that for a belt and pulley system, the linear velocity of the belt is constant. This means that the product of the radius and the angular velocity of each pulley must be the same.