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The day before a show, a theatre had sold adult and child tickets in the ratio 8:3. On the day of the show, the theatre sold 30 more adult tickets and no more child tickets. The ratio of adult to child tickets sold became 7 : 2. Work out how many adult tickets had been sold the day before the show.​

1 Answer

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Let's assume that the theatre sold 8x adult tickets and 3x child tickets the day before the show, so the ratio of adult to child tickets sold was 8:3.

On the day of the show, the theatre sold 30 more adult tickets, so the total number of adult tickets sold became 8x + 30. The number of child tickets sold remained the same, so it was 3x.

The ratio of adult to child tickets sold on the day of the show was 7:2. So, we can write:

(8x + 30)/3x = 7/2

To solve for x, we can cross-multiply and simplify:

2(8x + 30) = 21x
16x + 60 = 21x
5x = 60
x = 12

Therefore, the theatre sold 8x adult tickets the day before the show, which is:

8x = 8(12) = 96 adult tickets.

So, the theatre sold 96 adult tickets and 3x child tickets (3 x 12 = 36) the day before the show, in the ratio 8:3.
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User Edovino
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