Question

Find the first four terms of the sequence defined below, where n represents the position of a term in the sequence. Start with n = 1

an = 2(2)n​

Answer 1

Answer:

The first four terms of the sequence are 4, 8, 16, and 32.

Explanation:

The given sequence is defined by the formula:

an = 2(2)n

We can find the first four terms of the sequence by substituting the values of n = 1, 2, 3, and 4:

a1 = 2(2)^1 = 4
a2 = 2(2)^2 = 8
a3 = 2(2)^3 = 16
a4 = 2(2)^4 = 32

Therefore, the first four terms of the sequence are 4, 8, 16, and 32.