Question

What is the molarity of a sugar solution at 25°C that has 100.0 g of glucose, C6H12O6 (molar mass = 180 g/mol) dissolved in 1.50 L of water?​

Answer 1

Molarity also known as molar concentration is a measurement of moles of a solute compared to the total volume of the solution.

Some general formulas to help us answer this question:

`C=(n)/(v)`

• C= molar concentration/molarity (M or mol/L)

• n= moles of solute

• v= volume of solution (measured in L)

`MM=(m)/(n)`

• MM = molar mass (g/mol)
• m= mass (g)
• n = moles

To calculate the molarity we must first find moles. This is possible given the mass of solute (glucose) and the molar mass of glucose.

Rearranging the second equation we get :
`n=(m)/(MM)`

`(100.0g)/(180g/mol) =0.5556 mol`

Now we can use
`C=n/v` to calculate molarity

`C=(0.5556mol)/(1.50L)`

`C = 0.370 mol/L`