Let's assume that the two consecutive odd numbers are (2n+1) and (2n+3), where n is any natural number.
Their product would be:
(2n+1) x (2n+3) = 4n^2 + 8n + 3
We can see that this expression always results in an odd number.
To prove this, let's express any odd number as 2m+1, where m is any natural number.
If we substitute 2m+1 in the expression above, we get:
4n^2 + 8n + 3 = 2(2n^2 + 4n + 1) + 1
We can clearly see that this is an odd number since it is in the form 2k+1, where k is any integer.
Therefore, the product of two consecutive odd natural numbers is always an odd number.