Question

The first bag contains 6 red marbles, 5 blue marbles and 4 green marbles.

The second bag contains 3 red marbles, 2 blue marbles, and 4 green marbles.
What is the probability that Eric will select a red marble form each bag?

Answer 1

73.33%

Explanation:

We Know

The first bag contains 6 red marbles, 5 blue marbles, and 4 green marbles.

6 + 5 + 4 = 15 marbles in the first bag.

The second bag contains 3 red marbles, 2 blue marbles, and 4 green marbles.

3 + 2 + 4 = 9 marbles in the second bag.

What is the probability that Eric will select a red marble from each bag?

Let's solve

First bag: (6 ÷ 15) x 100 = 40%

Second bag: (3 ÷ 9) x 100 ≈ 33.33%

40 + 33.33 = 73.33%

So, the probability that Eric will select a red marble from each bag is ≈ 73.33%