A) When the balloon is carried up the mountain, the air pressure outside the balloon decreases while the temperature remains the same. The volume of the balloon may also change depending on how the air inside the balloon behaves.
B) The air pressure inside the balloon cannot decrease to match the outside pressure because the balloon is a closed system. The pressure inside the balloon remains constant unless there is a leak or some other means of air escaping.
C) The volume occupied by the air inside the balloon may change because the air expands as the pressure decreases. However, the extent to which the volume changes depends on how much the pressure changes and how much the temperature changes. If the temperature were to decrease, the air inside the balloon would contract, further reducing the volume.
D) To solve for the new volume of the balloon, we can use the combined gas law:
(P1V1)/T1 = (P2V2)/T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2 and T2 are the final pressure and temperature, respectively.
Plugging in the given values, we get:
(1.0 atm)(240 mL)/(298 K) = (0.75 atm)(V2)/(298 K)
Solving for V2, we get:
V2 = (1.0 atm)(240 mL)(0.75 atm)/(298 K)
V2 = 180 mL
Therefore, the new volume of the balloon is approximately 180 mL.