Question

A 3.0 L balloon holds 6.00 moles of hydrogen gas. If the temperature in the tank is 40.0°F.

what is the pressure in kPa?
1.925 kPa
51.41 kPa
0.01944 kPa
5,209.12 kPa

Answer 1

B) 51.41 kPa

Step-by-step explanation:

We can use the ideal gas law to solve this problem: PV = nRT

where:

P = pressure (in kPa)

V = volume (in L)

n = moles of gas

R = gas constant = 8.314 J/(mol K)

T = temperature (in K)

First, we need to convert the temperature to Kelvin:

T = (40.0 + 273.15) K = 313.15 K

Next, we can rearrange the ideal gas law to solve for P:

P = nRT/V

Substituting the given values, we get:

P = (6.00 mol) * (8.314 J/(mol K)) * (313.15 K) / (3.0 L) = 51.41 kPa

Therefore, the pressure in the balloon is 51.41 kPa, which is option B.