Question

Which is the percent composition of phosphorus in Zn3(PO4)2?

Select one:
a. 9.66 %
b. 24.01 %
c. 50.1 %
d. 16.1 %

Answer 1

The correct answer is D. 16.1%. Zn3(PO4)2 has three zinc atoms, two phosphorus atoms and eight oxygen atoms. The molar mass of Zn3(PO4)2 is 377.3 g/mol. The mass of phosphorus in one mole of Zn3(PO4)2 is 2 x 31.97 g = 63.94 g. Therefore, the percent by mass of phosphorus in Zn3(PO4)2 is 63.94/377.3 x 100 = 16.87%, which is 16.1% when rounded to the nearest whole number.

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