Question

Please help, im struggling with this and need to get it done now.

Answer 1

`√(x+2)=x-4\implies (√(x+2))^2=(x-4)^2\implies x+2=x^2-8x+16 \\\\\\ 0=x^2-9x+14\implies 0=(x-7)(x-2)\implies x= \begin{cases} 7 ~~ \textit{\LARGE \checkmark}\\ 2 ~~ \bigotimes \end{cases}`

why is x = 2 not good? well, plug it in, making the assumption that we're using only the positive root, 2 ≠ -2.