Question

which equation in standard form has a graph that passes through the point (5,4) and has a slope of -2/3? A-3x-10y=44 B-2x+3y=22 c-3x-2y=-5 D- 6x-12y=-15

Answer 1

Answer: B

Explanation:

`(x1,y1)=(5,4)`

Point slope form:

`y-y_(1)=m(x-x_(1) )`

`m=-(2)/(3)`

Thus, we have:


`y-4=-(2)/(3)(x-5)`

Use Distributive property

`y-4=-(2)/(3)x+(10)/(3)`

Add 4 to both sides.

`y=-(2)/(3)x+(10)/(3)+(4)/(1)`

This equals:


`y=-(2)/(3)x+(10)/(3)+(12)/(3)`

`y=-(2)/(3)x+(22)/(3)`

We need to turn this into standard form.

`Ax+By=C`

Multiplying 3 to our original equation we have:


`3y=-2x+22`

Adding 2x to both sides, we get:

`2x+3y=22`

Therefore, the answer is B. Hope this helps!!!