Answer:
To expand (x-y)³ using Pascal’s triangle, we can write:
1
1 1
1 2 1
1 3 3 1
Each row of the triangle represents the coefficients of the binomial expansion of (a+b)ⁿ, with the top row being n=0.
So for (x-y)³, we take the fourth row of the triangle (starting with n=0), and substitute x and y into the formula, alternating the signs of y:
1x³ + 3x²(-y) + 3x(-y)² + 1(-y)³
= x³ - 3x²y + 3xy² - y³
Thus, (x-y)³ = x³ - 3x²y + 3xy² - y³.