Question

What is the theoretical yield of vanadium that can be produced by the reaction of 40.0 g

of V2O5 with 40.0 g of calcium based on the following chemical reaction?
V2O5(s) + 5Ca(l) = 2V(l) + 5CaO(s)
A) 5.6 g B) 11.2 C) 20.3 g D) 22.4 g E) 40.0 g

Answer 1

The theoretical yield of vanadium that can be produced by the reaction is (option A). approximately 5.6 g.

Step-by-step explanation:

To find the theoretical yield of vanadium, we need to use stoichiometry. The balanced equation tells us that 1 mole of V2O5 produces 2 moles of V. First, we need to convert the mass of V2O5 to moles using its molar mass. Then, we use the mole ratio to determine the number of moles of V that can be produced. Finally, we convert the moles of V to grams using its molar mass.

Given:

Mass of V2O5 = 40.0 g

Molar mass of V2O5 = 181.88 g/mol

Using the conversion:

40.0 g V2O5 * (1 mol V2O5 / 181.88 g V2O5) * (2 mol V / 1 mol V2O5) * (50.94 g V / 1 mol V) = 5.57 g V

Therefore, the theoretical yield of vanadium that can be produced is approximately 5.6 g (option A).